C Program To Display Switch…Case Statement.

The following program asks user an arithmetic operator (+,-,*,/) and two operands and perform the corresponding calculation on the operands.

# include <stdio.h>

int main() {

char o;

float num1,num2;

printf("Enter an operator: either + or - or * or /\n\n=> ");

scanf("%c",&o);

printf("\nEnter two numbers:\n");

scanf("%f%f",&num1,&num2);

switch(o) {

case '+':

printf("\n%.1f + %.1f = %.1f\n",num1, num2, num1+num2);

break;

case '-':

printf("\n%.1f - %.1f = %.1f\n",num1, num2, num1-num2);

break;

case '*':

printf("\n%.1f * %.1f = %.1f\n",num1, num2, num1*num2);

break;

case '/':

printf("\n%.1f / %.1f = %.1f\n",num1, num2, num1/num2);

break;

default:

printf("\nError! operator is not correct.\n");

break;

}

return 0;

}